7(x-4)=-7(x+1)+22

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Solution for 7(x-4)=-7(x+1)+22 equation: 



7(x-4)=-7(x+1)+22

We move all terms to the left:

7(x-4)-(-7(x+1)+22)=0

We multiply parentheses

7x-(-7(x+1)+22)-28=0



We calculate terms in parentheses: -(-7(x+1)+22), so:

-7(x+1)+22

We multiply parentheses

-7x-7+22

We add all the numbers together, and all the variables

-7x+15

Back to the equation:

-(-7x+15)



We get rid of parentheses

7x+7x-15-28=0

We add all the numbers together, and all the variables

14x-43=0

We move all terms containing x to the left, all other terms to the right

14x=43

x=43/14

x=3+1/14

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