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7(x-4)=2(x+5)
We move all terms to the left:
7(x-4)-(2(x+5))=0
We multiply parentheses
7x-(2(x+5))-28=0
We calculate terms in parentheses: -(2(x+5)), so:We get rid of parentheses
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
7x-2x-10-28=0
We add all the numbers together, and all the variables
5x-38=0
We move all terms containing x to the left, all other terms to the right
5x=38
x=38/5
x=7+3/5
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