7(x-4)=3(2x+1)

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Solution for 7(x-4)=3(2x+1) equation: 



7(x-4)=3(2x+1)

We move all terms to the left:

7(x-4)-(3(2x+1))=0

We multiply parentheses

7x-(3(2x+1))-28=0



We calculate terms in parentheses: -(3(2x+1)), so:

3(2x+1)

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We get rid of parentheses

7x-6x-3-28=0

We add all the numbers together, and all the variables

x-31=0

We move all terms containing x to the left, all other terms to the right

x=31

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