7(x-4)=3(3+x)-1

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Solution for 7(x-4)=3(3+x)-1 equation:



7(x-4)=3(3+x)-1
We move all terms to the left:
7(x-4)-(3(3+x)-1)=0
We add all the numbers together, and all the variables
7(x-4)-(3(x+3)-1)=0
We multiply parentheses
7x-(3(x+3)-1)-28=0
We calculate terms in parentheses: -(3(x+3)-1), so:
3(x+3)-1
We multiply parentheses
3x+9-1
We add all the numbers together, and all the variables
3x+8
Back to the equation:
-(3x+8)
We get rid of parentheses
7x-3x-8-28=0
We add all the numbers together, and all the variables
4x-36=0
We move all terms containing x to the left, all other terms to the right
4x=36
x=36/4
x=9

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