7(x-4)=3(x-2)+2

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Solution for 7(x-4)=3(x-2)+2 equation: 



7(x-4)=3(x-2)+2

We move all terms to the left:

7(x-4)-(3(x-2)+2)=0

We multiply parentheses

7x-(3(x-2)+2)-28=0



We calculate terms in parentheses: -(3(x-2)+2), so:

3(x-2)+2

We multiply parentheses

3x-6+2

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We get rid of parentheses

7x-3x+4-28=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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