7(x-4)=3x+6+3x+1

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Solution for 7(x-4)=3x+6+3x+1 equation: 



7(x-4)=3x+6+3x+1

We move all terms to the left:

7(x-4)-(3x+6+3x+1)=0

We add all the numbers together, and all the variables

7(x-4)-(6x+7)=0

We multiply parentheses

7x-(6x+7)-28=0

We get rid of parentheses

7x-6x-7-28=0

We add all the numbers together, and all the variables

x-35=0

We move all terms containing x to the left, all other terms to the right

x=35

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