7(x-4)=3x+6+3x+1

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Solution for 7(x-4)=3x+6+3x+1 equation:



7(x-4)=3x+6+3x+1
We move all terms to the left:
7(x-4)-(3x+6+3x+1)=0
We add all the numbers together, and all the variables
7(x-4)-(6x+7)=0
We multiply parentheses
7x-(6x+7)-28=0
We get rid of parentheses
7x-6x-7-28=0
We add all the numbers together, and all the variables
x-35=0
We move all terms containing x to the left, all other terms to the right
x=35

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