7(x-4)=6(x+4)-2

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Solution for 7(x-4)=6(x+4)-2 equation: 



7(x-4)=6(x+4)-2

We move all terms to the left:

7(x-4)-(6(x+4)-2)=0

We multiply parentheses

7x-(6(x+4)-2)-28=0



We calculate terms in parentheses: -(6(x+4)-2), so:

6(x+4)-2

We multiply parentheses

6x+24-2

We add all the numbers together, and all the variables

6x+22

Back to the equation:

-(6x+22)



We get rid of parentheses

7x-6x-22-28=0

We add all the numbers together, and all the variables

x-50=0

We move all terms containing x to the left, all other terms to the right

x=50

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