7(x-4)=6(x+4)-2

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Solution for 7(x-4)=6(x+4)-2 equation:



7(x-4)=6(x+4)-2
We move all terms to the left:
7(x-4)-(6(x+4)-2)=0
We multiply parentheses
7x-(6(x+4)-2)-28=0
We calculate terms in parentheses: -(6(x+4)-2), so:
6(x+4)-2
We multiply parentheses
6x+24-2
We add all the numbers together, and all the variables
6x+22
Back to the equation:
-(6x+22)
We get rid of parentheses
7x-6x-22-28=0
We add all the numbers together, and all the variables
x-50=0
We move all terms containing x to the left, all other terms to the right
x=50

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