7(x-5)+12=4(x-5)

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Solution for 7(x-5)+12=4(x-5) equation: 



7(x-5)+12=4(x-5)

We move all terms to the left:

7(x-5)+12-(4(x-5))=0

We multiply parentheses

7x-(4(x-5))-35+12=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

7x-(4x-20)-23=0

We get rid of parentheses

7x-4x+20-23=0

We add all the numbers together, and all the variables

3x-3=0

We move all terms containing x to the left, all other terms to the right

3x=3

x=3/3

x=1

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