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7(x-5)+2(6-x)=12
We move all terms to the left:
7(x-5)+2(6-x)-(12)=0
We add all the numbers together, and all the variables
7(x-5)+2(-1x+6)-12=0
We multiply parentheses
7x-2x-35+12-12=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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