7(x-5)+5(x-2)=3(x+3)-2(x+2)

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Solution for 7(x-5)+5(x-2)=3(x+3)-2(x+2) equation: 



7(x-5)+5(x-2)=3(x+3)-2(x+2)

We move all terms to the left:

7(x-5)+5(x-2)-(3(x+3)-2(x+2))=0

We multiply parentheses

7x+5x-(3(x+3)-2(x+2))-35-10=0



We calculate terms in parentheses: -(3(x+3)-2(x+2)), so:

3(x+3)-2(x+2)

We multiply parentheses

3x-2x+9-4

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We add all the numbers together, and all the variables

12x-(x+5)-45=0

We get rid of parentheses

12x-x-5-45=0

We add all the numbers together, and all the variables

11x-50=0

We move all terms containing x to the left, all other terms to the right

11x=50

x=50/11

x=4+6/11

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