7(x-5)=19-3(x+19)

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Solution for 7(x-5)=19-3(x+19) equation: 



7(x-5)=19-3(x+19)

We move all terms to the left:

7(x-5)-(19-3(x+19))=0

We multiply parentheses

7x-(19-3(x+19))-35=0



We calculate terms in parentheses: -(19-3(x+19)), so:

19-3(x+19)

determiningTheFunctionDomain
-3(x+19)+19

We multiply parentheses

-3x-57+19

We add all the numbers together, and all the variables

-3x-38

Back to the equation:

-(-3x-38)



We get rid of parentheses

7x+3x+38-35=0

We add all the numbers together, and all the variables

10x+3=0

We move all terms containing x to the left, all other terms to the right

10x=-3

x=-3/10

x=-3/10

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