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7(x-5)=2(5-x)
We move all terms to the left:
7(x-5)-(2(5-x))=0
We add all the numbers together, and all the variables
7(x-5)-(2(-1x+5))=0
We multiply parentheses
7x-(2(-1x+5))-35=0
We calculate terms in parentheses: -(2(-1x+5)), so:We get rid of parentheses
2(-1x+5)
We multiply parentheses
-2x+10
Back to the equation:
-(-2x+10)
7x+2x-10-35=0
We add all the numbers together, and all the variables
9x-45=0
We move all terms containing x to the left, all other terms to the right
9x=45
x=45/9
x=5
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