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7(x-5)=3(5-x)
We move all terms to the left:
7(x-5)-(3(5-x))=0
We add all the numbers together, and all the variables
7(x-5)-(3(-1x+5))=0
We multiply parentheses
7x-(3(-1x+5))-35=0
We calculate terms in parentheses: -(3(-1x+5)), so:We get rid of parentheses
3(-1x+5)
We multiply parentheses
-3x+15
Back to the equation:
-(-3x+15)
7x+3x-15-35=0
We add all the numbers together, and all the variables
10x-50=0
We move all terms containing x to the left, all other terms to the right
10x=50
x=50/10
x=5
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