7(x-5)=3(x+12)

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Solution for 7(x-5)=3(x+12) equation: 



7(x-5)=3(x+12)

We move all terms to the left:

7(x-5)-(3(x+12))=0

We multiply parentheses

7x-(3(x+12))-35=0



We calculate terms in parentheses: -(3(x+12)), so:

3(x+12)

We multiply parentheses

3x+36

Back to the equation:

-(3x+36)



We get rid of parentheses

7x-3x-36-35=0

We add all the numbers together, and all the variables

4x-71=0

We move all terms containing x to the left, all other terms to the right

4x=71

x=71/4

x=17+3/4

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