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7(x-5)=3(x+2)
We move all terms to the left:
7(x-5)-(3(x+2))=0
We multiply parentheses
7x-(3(x+2))-35=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
7x-3x-6-35=0
We add all the numbers together, and all the variables
4x-41=0
We move all terms containing x to the left, all other terms to the right
4x=41
x=41/4
x=10+1/4
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