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7(x-5)=6(x-2)
We move all terms to the left:
7(x-5)-(6(x-2))=0
We multiply parentheses
7x-(6(x-2))-35=0
We calculate terms in parentheses: -(6(x-2)), so:We get rid of parentheses
6(x-2)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
7x-6x+12-35=0
We add all the numbers together, and all the variables
x-23=0
We move all terms containing x to the left, all other terms to the right
x=23
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