7(x-8)+37=3(x-5)

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Solution for 7(x-8)+37=3(x-5) equation: 



7(x-8)+37=3(x-5)

We move all terms to the left:

7(x-8)+37-(3(x-5))=0

We multiply parentheses

7x-(3(x-5))-56+37=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We add all the numbers together, and all the variables

7x-(3x-15)-19=0

We get rid of parentheses

7x-3x+15-19=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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