7(x-8)-3=2(x-4)+17

Solution for 7(x-8)-3=2(x-4)+17 equation:

7(x-8)-3=2(x-4)+17

We move all terms to the left:

7(x-8)-3-(2(x-4)+17)=0

We multiply parentheses

7x-(2(x-4)+17)-56-3=0


We calculate terms in parentheses: -(2(x-4)+17), so:

2(x-4)+17

We multiply parentheses

2x-8+17

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)


We add all the numbers together, and all the variables

7x-(2x+9)-59=0

We get rid of parentheses

7x-2x-9-59=0

We add all the numbers together, and all the variables

5x-68=0

We move all terms containing x to the left, all other terms to the right

5x=68

x=68/5

x=13+3/5