7(x-8)=-8(x-5)-x

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Solution for 7(x-8)=-8(x-5)-x equation: 



7(x-8)=-8(x-5)-x

We move all terms to the left:

7(x-8)-(-8(x-5)-x)=0

We multiply parentheses

7x-(-8(x-5)-x)-56=0



We calculate terms in parentheses: -(-8(x-5)-x), so:

-8(x-5)-x

We add all the numbers together, and all the variables

-1x-8(x-5)

We multiply parentheses

-1x-8x+40

We add all the numbers together, and all the variables

-9x+40

Back to the equation:

-(-9x+40)



We get rid of parentheses

7x+9x-40-56=0

We add all the numbers together, and all the variables

16x-96=0

We move all terms containing x to the left, all other terms to the right

16x=96

x=96/16

x=6

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