7(x2+6)=1

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Solution for 7(x2+6)=1 equation: 



7(x2+6)=1

We move all terms to the left:

7(x2+6)-(1)=0

We add all the numbers together, and all the variables

7(+x^2+6)-1=0

We multiply parentheses

7x^2+42-1=0

We add all the numbers together, and all the variables

7x^2+41=0

a = 7; b = 0; c = +41;
Δ = b2-4ac
Δ = 02-4·7·41
Δ = -1148
Delta is less than zero, so there is no solution for the equation

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