7(y+1)-3y=5+4(2y-11)

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Solution for 7(y+1)-3y=5+4(2y-11) equation: 



7(y+1)-3y=5+4(2y-11)

We move all terms to the left:

7(y+1)-3y-(5+4(2y-11))=0

We add all the numbers together, and all the variables

-3y+7(y+1)-(5+4(2y-11))=0

We multiply parentheses

-3y+7y-(5+4(2y-11))+7=0



We calculate terms in parentheses: -(5+4(2y-11)), so:

5+4(2y-11)

determiningTheFunctionDomain
4(2y-11)+5

We multiply parentheses

8y-44+5

We add all the numbers together, and all the variables

8y-39

Back to the equation:

-(8y-39)



We add all the numbers together, and all the variables

4y-(8y-39)+7=0

We get rid of parentheses

4y-8y+39+7=0

We add all the numbers together, and all the variables

-4y+46=0

We move all terms containing y to the left, all other terms to the right

-4y=-46

y=-46/-4

y=11+1/2

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