7(y+1)=-3(2y-3)+7y

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Solution for 7(y+1)=-3(2y-3)+7y equation: 



7(y+1)=-3(2y-3)+7y

We move all terms to the left:

7(y+1)-(-3(2y-3)+7y)=0

We multiply parentheses

7y-(-3(2y-3)+7y)+7=0



We calculate terms in parentheses: -(-3(2y-3)+7y), so:

-3(2y-3)+7y

We add all the numbers together, and all the variables

7y-3(2y-3)

We multiply parentheses

7y-6y+9

We add all the numbers together, and all the variables

y+9

Back to the equation:

-(y+9)



We get rid of parentheses

7y-y-9+7=0

We add all the numbers together, and all the variables

6y-2=0

We move all terms containing y to the left, all other terms to the right

6y=2

y=2/6

y=1/3

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