7(y+1)=3y+39

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Solution for 7(y+1)=3y+39 equation: 



7(y+1)=3y+39

We move all terms to the left:

7(y+1)-(3y+39)=0

We multiply parentheses

7y-(3y+39)+7=0

We get rid of parentheses

7y-3y-39+7=0

We add all the numbers together, and all the variables

4y-32=0

We move all terms containing y to the left, all other terms to the right

4y=32

y=32/4

y=8

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