7(y+1)=3y-1

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Solution for 7(y+1)=3y-1 equation: 



7(y+1)=3y-1

We move all terms to the left:

7(y+1)-(3y-1)=0

We multiply parentheses

7y-(3y-1)+7=0

We get rid of parentheses

7y-3y+1+7=0

We add all the numbers together, and all the variables

4y+8=0

We move all terms containing y to the left, all other terms to the right

4y=-8

y=-8/4

y=-2

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