7(y+1)=3y-13

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Solution for 7(y+1)=3y-13 equation: 



7(y+1)=3y-13

We move all terms to the left:

7(y+1)-(3y-13)=0

We multiply parentheses

7y-(3y-13)+7=0

We get rid of parentheses

7y-3y+13+7=0

We add all the numbers together, and all the variables

4y+20=0

We move all terms containing y to the left, all other terms to the right

4y=-20

y=-20/4

y=-5

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