7(y+1)=4(3y-2)

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Solution for 7(y+1)=4(3y-2) equation:


Simplifying
7(y + 1) = 4(3y + -2)

Reorder the terms:
7(1 + y) = 4(3y + -2)
(1 * 7 + y * 7) = 4(3y + -2)
(7 + 7y) = 4(3y + -2)

Reorder the terms:
7 + 7y = 4(-2 + 3y)
7 + 7y = (-2 * 4 + 3y * 4)
7 + 7y = (-8 + 12y)

Solving
7 + 7y = -8 + 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.
7 + 7y + -12y = -8 + 12y + -12y

Combine like terms: 7y + -12y = -5y
7 + -5y = -8 + 12y + -12y

Combine like terms: 12y + -12y = 0
7 + -5y = -8 + 0
7 + -5y = -8

Add '-7' to each side of the equation.
7 + -7 + -5y = -8 + -7

Combine like terms: 7 + -7 = 0
0 + -5y = -8 + -7
-5y = -8 + -7

Combine like terms: -8 + -7 = -15
-5y = -15

Divide each side by '-5'.
y = 3

Simplifying
y = 3

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