7(y+1)=4y+1

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Solution for 7(y+1)=4y+1 equation: 



7(y+1)=4y+1

We move all terms to the left:

7(y+1)-(4y+1)=0

We multiply parentheses

7y-(4y+1)+7=0

We get rid of parentheses

7y-4y-1+7=0

We add all the numbers together, and all the variables

3y+6=0

We move all terms containing y to the left, all other terms to the right

3y=-6

y=-6/3

y=-2

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