7(y+10)+y=3(y+4)-4

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Solution for 7(y+10)+y=3(y+4)-4 equation: 



7(y+10)+y=3(y+4)-4

We move all terms to the left:

7(y+10)+y-(3(y+4)-4)=0

We add all the numbers together, and all the variables

y+7(y+10)-(3(y+4)-4)=0

We multiply parentheses

y+7y-(3(y+4)-4)+70=0



We calculate terms in parentheses: -(3(y+4)-4), so:

3(y+4)-4

We multiply parentheses

3y+12-4

We add all the numbers together, and all the variables

3y+8

Back to the equation:

-(3y+8)



We add all the numbers together, and all the variables

8y-(3y+8)+70=0

We get rid of parentheses

8y-3y-8+70=0

We add all the numbers together, and all the variables

5y+62=0

We move all terms containing y to the left, all other terms to the right

5y=-62

y=-62/5

y=-12+2/5

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