7(y+2)+y=3(y+4)-8

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Solution for 7(y+2)+y=3(y+4)-8 equation: 


Simplifying
7(y + 2) + y = 3(y + 4) + -8

Reorder the terms:
7(2 + y) + y = 3(y + 4) + -8
(2 * 7 + y * 7) + y = 3(y + 4) + -8
(14 + 7y) + y = 3(y + 4) + -8

Combine like terms: 7y + y = 8y
14 + 8y = 3(y + 4) + -8

Reorder the terms:
14 + 8y = 3(4 + y) + -8
14 + 8y = (4 * 3 + y * 3) + -8
14 + 8y = (12 + 3y) + -8

Reorder the terms:
14 + 8y = 12 + -8 + 3y

Combine like terms: 12 + -8 = 4
14 + 8y = 4 + 3y

Solving
14 + 8y = 4 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
14 + 8y + -3y = 4 + 3y + -3y

Combine like terms: 8y + -3y = 5y
14 + 5y = 4 + 3y + -3y

Combine like terms: 3y + -3y = 0
14 + 5y = 4 + 0
14 + 5y = 4

Add '-14' to each side of the equation.
14 + -14 + 5y = 4 + -14

Combine like terms: 14 + -14 = 0
0 + 5y = 4 + -14
5y = 4 + -14

Combine like terms: 4 + -14 = -10
5y = -10

Divide each side by '5'.
y = -2

Simplifying
y = -2

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