7(y+2)-6(y+1)=3

Solution for 7(y+2)-6(y+1)=3 equation:

Simplifying
7(y + 2) + -6(y + 1) = 3

Reorder the terms:
7(2 + y) + -6(y + 1) = 3
(2 * 7 + y * 7) + -6(y + 1) = 3
(14 + 7y) + -6(y + 1) = 3

Reorder the terms:
14 + 7y + -6(1 + y) = 3
14 + 7y + (1 * -6 + y * -6) = 3
14 + 7y + (-6 + -6y) = 3

Reorder the terms:
14 + -6 + 7y + -6y = 3

Combine like terms: 14 + -6 = 8
8 + 7y + -6y = 3

Combine like terms: 7y + -6y = 1y
8 + 1y = 3

Solving
8 + 1y = 3

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 1y = 3 + -8

Combine like terms: 8 + -8 = 0
0 + 1y = 3 + -8
1y = 3 + -8

Combine like terms: 3 + -8 = -5
1y = -5

Divide each side by '1'.
y = -5

Simplifying
y = -5