7(y+2)=-6y+40

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Solution for 7(y+2)=-6y+40 equation: 



7(y+2)=-6y+40

We move all terms to the left:

7(y+2)-(-6y+40)=0

We multiply parentheses

7y-(-6y+40)+14=0

We get rid of parentheses

7y+6y-40+14=0

We add all the numbers together, and all the variables

13y-26=0

We move all terms containing y to the left, all other terms to the right

13y=26

y=26/13

y=2

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