7(y+3)+9=5(y-2)-3y

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Solution for 7(y+3)+9=5(y-2)-3y equation: 



7(y+3)+9=5(y-2)-3y

We move all terms to the left:

7(y+3)+9-(5(y-2)-3y)=0

We multiply parentheses

7y-(5(y-2)-3y)+21+9=0



We calculate terms in parentheses: -(5(y-2)-3y), so:

5(y-2)-3y

We add all the numbers together, and all the variables

-3y+5(y-2)

We multiply parentheses

-3y+5y-10

We add all the numbers together, and all the variables

2y-10

Back to the equation:

-(2y-10)



We add all the numbers together, and all the variables

7y-(2y-10)+30=0

We get rid of parentheses

7y-2y+10+30=0

We add all the numbers together, and all the variables

5y+40=0

We move all terms containing y to the left, all other terms to the right

5y=-40

y=-40/5

y=-8

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