7(y+3)=-3(2y-6)+7Y

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Solution for 7(y+3)=-3(2y-6)+7Y equation: 



7(y+3)=-3(2y-6)+7

We move all terms to the left:

7(y+3)-(-3(2y-6)+7)=0

We multiply parentheses

7y-(-3(2y-6)+7)+21=0



We calculate terms in parentheses: -(-3(2y-6)+7), so:

-3(2y-6)+7

We multiply parentheses

-6y+18+7

We add all the numbers together, and all the variables

-6y+25

Back to the equation:

-(-6y+25)



We get rid of parentheses

7y+6y-25+21=0

We add all the numbers together, and all the variables

13y-4=0

We move all terms containing y to the left, all other terms to the right

13y=4

y=4/13

y=4/13

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