7(y+3)=3y+37

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Solution for 7(y+3)=3y+37 equation: 



7(y+3)=3y+37

We move all terms to the left:

7(y+3)-(3y+37)=0

We multiply parentheses

7y-(3y+37)+21=0

We get rid of parentheses

7y-3y-37+21=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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