7(y+3)=5y+21

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Solution for 7(y+3)=5y+21 equation: 



7(y+3)=5y+21

We move all terms to the left:

7(y+3)-(5y+21)=0

We multiply parentheses

7y-(5y+21)+21=0

We get rid of parentheses

7y-5y-21+21=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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