7(y+4)+y=4(y+2)+7

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Solution for 7(y+4)+y=4(y+2)+7 equation: 



7(y+4)+y=4(y+2)+7

We move all terms to the left:

7(y+4)+y-(4(y+2)+7)=0

We add all the numbers together, and all the variables

y+7(y+4)-(4(y+2)+7)=0

We multiply parentheses

y+7y-(4(y+2)+7)+28=0



We calculate terms in parentheses: -(4(y+2)+7), so:

4(y+2)+7

We multiply parentheses

4y+8+7

We add all the numbers together, and all the variables

4y+15

Back to the equation:

-(4y+15)



We add all the numbers together, and all the variables

8y-(4y+15)+28=0

We get rid of parentheses

8y-4y-15+28=0

We add all the numbers together, and all the variables

4y+13=0

We move all terms containing y to the left, all other terms to the right

4y=-13

y=-13/4

y=-3+1/4

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