7(y+4)+y=4(y+2)-4

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Solution for 7(y+4)+y=4(y+2)-4 equation: 



7(y+4)+y=4(y+2)-4

We move all terms to the left:

7(y+4)+y-(4(y+2)-4)=0

We add all the numbers together, and all the variables

y+7(y+4)-(4(y+2)-4)=0

We multiply parentheses

y+7y-(4(y+2)-4)+28=0



We calculate terms in parentheses: -(4(y+2)-4), so:

4(y+2)-4

We multiply parentheses

4y+8-4

We add all the numbers together, and all the variables

4y+4

Back to the equation:

-(4y+4)



We add all the numbers together, and all the variables

8y-(4y+4)+28=0

We get rid of parentheses

8y-4y-4+28=0

We add all the numbers together, and all the variables

4y+24=0

We move all terms containing y to the left, all other terms to the right

4y=-24

y=-24/4

y=-6

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