7(y+4)-4(2y-3)=40

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Solution for 7(y+4)-4(2y-3)=40 equation: 


Simplifying
7(y + 4) + -4(2y + -3) = 40

Reorder the terms:
7(4 + y) + -4(2y + -3) = 40
(4 * 7 + y * 7) + -4(2y + -3) = 40
(28 + 7y) + -4(2y + -3) = 40

Reorder the terms:
28 + 7y + -4(-3 + 2y) = 40
28 + 7y + (-3 * -4 + 2y * -4) = 40
28 + 7y + (12 + -8y) = 40

Reorder the terms:
28 + 12 + 7y + -8y = 40

Combine like terms: 28 + 12 = 40
40 + 7y + -8y = 40

Combine like terms: 7y + -8y = -1y
40 + -1y = 40

Add '-40' to each side of the equation.
40 + -40 + -1y = 40 + -40

Combine like terms: 40 + -40 = 0
0 + -1y = 40 + -40
-1y = 40 + -40

Combine like terms: 40 + -40 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0

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