7(y+4)=-2(3y-5)+3y

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Solution for 7(y+4)=-2(3y-5)+3y equation: 



7(y+4)=-2(3y-5)+3y

We move all terms to the left:

7(y+4)-(-2(3y-5)+3y)=0

We multiply parentheses

7y-(-2(3y-5)+3y)+28=0



We calculate terms in parentheses: -(-2(3y-5)+3y), so:

-2(3y-5)+3y

We add all the numbers together, and all the variables

3y-2(3y-5)

We multiply parentheses

3y-6y+10

We add all the numbers together, and all the variables

-3y+10

Back to the equation:

-(-3y+10)



We get rid of parentheses

7y+3y-10+28=0

We add all the numbers together, and all the variables

10y+18=0

We move all terms containing y to the left, all other terms to the right

10y=-18

y=-18/10

y=-1+4/5

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