7(y+4)=-4(3y-6)+5y

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Solution for 7(y+4)=-4(3y-6)+5y equation: 



7(y+4)=-4(3y-6)+5y

We move all terms to the left:

7(y+4)-(-4(3y-6)+5y)=0

We multiply parentheses

7y-(-4(3y-6)+5y)+28=0



We calculate terms in parentheses: -(-4(3y-6)+5y), so:

-4(3y-6)+5y

We add all the numbers together, and all the variables

5y-4(3y-6)

We multiply parentheses

5y-12y+24

We add all the numbers together, and all the variables

-7y+24

Back to the equation:

-(-7y+24)



We get rid of parentheses

7y+7y-24+28=0

We add all the numbers together, and all the variables

14y+4=0

We move all terms containing y to the left, all other terms to the right

14y=-4

y=-4/14

y=-2/7

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