7(y+7)+y=4(y+4)-4

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Solution for 7(y+7)+y=4(y+4)-4 equation: 



7(y+7)+y=4(y+4)-4

We move all terms to the left:

7(y+7)+y-(4(y+4)-4)=0

We add all the numbers together, and all the variables

y+7(y+7)-(4(y+4)-4)=0

We multiply parentheses

y+7y-(4(y+4)-4)+49=0



We calculate terms in parentheses: -(4(y+4)-4), so:

4(y+4)-4

We multiply parentheses

4y+16-4

We add all the numbers together, and all the variables

4y+12

Back to the equation:

-(4y+12)



We add all the numbers together, and all the variables

8y-(4y+12)+49=0

We get rid of parentheses

8y-4y-12+49=0

We add all the numbers together, and all the variables

4y+37=0

We move all terms containing y to the left, all other terms to the right

4y=-37

y=-37/4

y=-9+1/4

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