7(y+8)+y=3(y+2)-5

Solution for 7(y+8)+y=3(y+2)-5 equation:

7(y+8)+y=3(y+2)-5

We move all terms to the left:

7(y+8)+y-(3(y+2)-5)=0

We add all the numbers together, and all the variables

y+7(y+8)-(3(y+2)-5)=0

We multiply parentheses

y+7y-(3(y+2)-5)+56=0


We calculate terms in parentheses: -(3(y+2)-5), so:

3(y+2)-5

We multiply parentheses

3y+6-5

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)


We add all the numbers together, and all the variables

8y-(3y+1)+56=0

We get rid of parentheses

8y-3y-1+56=0

We add all the numbers together, and all the variables

5y+55=0

We move all terms containing y to the left, all other terms to the right

5y=-55

y=-55/5

y=-11