7(y+8)+y=4(y+5)+7

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Solution for 7(y+8)+y=4(y+5)+7 equation: 



7(y+8)+y=4(y+5)+7

We move all terms to the left:

7(y+8)+y-(4(y+5)+7)=0

We add all the numbers together, and all the variables

y+7(y+8)-(4(y+5)+7)=0

We multiply parentheses

y+7y-(4(y+5)+7)+56=0



We calculate terms in parentheses: -(4(y+5)+7), so:

4(y+5)+7

We multiply parentheses

4y+20+7

We add all the numbers together, and all the variables

4y+27

Back to the equation:

-(4y+27)



We add all the numbers together, and all the variables

8y-(4y+27)+56=0

We get rid of parentheses

8y-4y-27+56=0

We add all the numbers together, and all the variables

4y+29=0

We move all terms containing y to the left, all other terms to the right

4y=-29

y=-29/4

y=-7+1/4

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