7(y+8)=3(y+5)+8

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Solution for 7(y+8)=3(y+5)+8 equation:



7(y+8)=3(y+5)+8
We move all terms to the left:
7(y+8)-(3(y+5)+8)=0
We multiply parentheses
7y-(3(y+5)+8)+56=0
We calculate terms in parentheses: -(3(y+5)+8), so:
3(y+5)+8
We multiply parentheses
3y+15+8
We add all the numbers together, and all the variables
3y+23
Back to the equation:
-(3y+23)
We get rid of parentheses
7y-3y-23+56=0
We add all the numbers together, and all the variables
4y+33=0
We move all terms containing y to the left, all other terms to the right
4y=-33
y=-33/4
y=-8+1/4

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