7(y-1)-8=-6(-5y+2)-8y

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Solution for 7(y-1)-8=-6(-5y+2)-8y equation: 



7(y-1)-8=-6(-5y+2)-8y

We move all terms to the left:

7(y-1)-8-(-6(-5y+2)-8y)=0

We multiply parentheses

7y-(-6(-5y+2)-8y)-7-8=0



We calculate terms in parentheses: -(-6(-5y+2)-8y), so:

-6(-5y+2)-8y

We add all the numbers together, and all the variables

-8y-6(-5y+2)

We multiply parentheses

-8y+30y-12

We add all the numbers together, and all the variables

22y-12

Back to the equation:

-(22y-12)



We add all the numbers together, and all the variables

7y-(22y-12)-15=0

We get rid of parentheses

7y-22y+12-15=0

We add all the numbers together, and all the variables

-15y-3=0

We move all terms containing y to the left, all other terms to the right

-15y=3

y=3/-15

y=-1/5

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