7(y-1)=(y+3)

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Solution for 7(y-1)=(y+3) equation:



7(y-1)=(y+3)
We move all terms to the left:
7(y-1)-((y+3))=0
We multiply parentheses
7y-((y+3))-7=0
We calculate terms in parentheses: -((y+3)), so:
(y+3)
We get rid of parentheses
y+3
Back to the equation:
-(y+3)
We get rid of parentheses
7y-y-3-7=0
We add all the numbers together, and all the variables
6y-10=0
We move all terms containing y to the left, all other terms to the right
6y=10
y=10/6
y=1+2/3

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