7(y-1)=4(y-1)+15

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Solution for 7(y-1)=4(y-1)+15 equation: 



7(y-1)=4(y-1)+15

We move all terms to the left:

7(y-1)-(4(y-1)+15)=0

We multiply parentheses

7y-(4(y-1)+15)-7=0



We calculate terms in parentheses: -(4(y-1)+15), so:

4(y-1)+15

We multiply parentheses

4y-4+15

We add all the numbers together, and all the variables

4y+11

Back to the equation:

-(4y+11)



We get rid of parentheses

7y-4y-11-7=0

We add all the numbers together, and all the variables

3y-18=0

We move all terms containing y to the left, all other terms to the right

3y=18

y=18/3

y=6

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