7(y-1)=5(y+3)

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Solution for 7(y-1)=5(y+3) equation: 



7(y-1)=5(y+3)

We move all terms to the left:

7(y-1)-(5(y+3))=0

We multiply parentheses

7y-(5(y+3))-7=0



We calculate terms in parentheses: -(5(y+3)), so:

5(y+3)

We multiply parentheses

5y+15

Back to the equation:

-(5y+15)



We get rid of parentheses

7y-5y-15-7=0

We add all the numbers together, and all the variables

2y-22=0

We move all terms containing y to the left, all other terms to the right

2y=22

y=22/2

y=11

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