7(y-15)=35(y+4)

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Solution for 7(y-15)=35(y+4) equation: 



7(y-15)=35(y+4)

We move all terms to the left:

7(y-15)-(35(y+4))=0

We multiply parentheses

7y-(35(y+4))-105=0



We calculate terms in parentheses: -(35(y+4)), so:

35(y+4)

We multiply parentheses

35y+140

Back to the equation:

-(35y+140)



We get rid of parentheses

7y-35y-140-105=0

We add all the numbers together, and all the variables

-28y-245=0

We move all terms containing y to the left, all other terms to the right

-28y=245

y=245/-28

y=-8+3/4

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