7(y-15)=4(6+y)

Solution for 7(y-15)=4(6+y) equation:

7(y-15)=4(6+y)

We move all terms to the left:

7(y-15)-(4(6+y))=0

We add all the numbers together, and all the variables

7(y-15)-(4(y+6))=0

We multiply parentheses

7y-(4(y+6))-105=0


We calculate terms in parentheses: -(4(y+6)), so:

4(y+6)

We multiply parentheses

4y+24

Back to the equation:

-(4y+24)


We get rid of parentheses

7y-4y-24-105=0

We add all the numbers together, and all the variables

3y-129=0

We move all terms containing y to the left, all other terms to the right

3y=129

y=129/3

y=43